EXPERIMENT NO. 4
Component : 1 * resistor, 1 * 5v1 400W Zener diode, 1* Diode 1N4007 .
Exercise: Vs = 10& 15v, =1K ohms.
10 volt 15V |
Volt drop V1: 4.30v 6.45 |
Volt drop V2: 0.70v 0.70V |
Volt drop V3: 5v 7.35V |
Volt drop V4: 5V 7.25V |
Calculated current A :
I = V/R = 10/1000 = 0.01 AMPS (1 A)
I = V/R = 14.80/1000 = 0.0148 AMPS (1.48 A)
In this series circuit V1 – Zener diode in reverse bias and takes about 5v to turn it on (gates open) and the switcing diode(V2) is in forward base. In there should voltage for V2 is ranged 0.6v-0.7v to turn it on, v3 is the total of (V1 + V2) voltage drop and the rest of the voltage is consumed in V4 which is giving us the total voltage supply.
V1 + V2 = V3 and V3 + V4 = SV
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