Tuesday, August 3, 2010

EXPERIMENT NO.4

EXPERIMENT NO. 4

Component : 1 * resistor, 1 * 5v1 400W Zener diode,  1* Diode 1N4007 .
Exercise:  Vs = 10& 15v, =1K ohms.






                              10 volt                  15V
Volt drop V1:         4.30v                    6.45
Volt drop V2:         0.70v                    0.70V
Volt drop V3:         5v                         7.35V                                                                   
Volt drop V4:         5V                        7.25V                                                               

Calculated current A :
I = V/R = 10/1000 = 0.01 AMPS (1 A)       
I = V/R = 14.80/1000 = 0.0148 AMPS (1.48 A)
In this series circuit V1 – Zener diode in reverse bias and takes about  5v to turn it on (gates open) and the switcing diode(V2) is in forward base. In there should voltage for V2 is ranged 0.6v-0.7v to turn it on, v3 is the total of (V1 + V2) voltage drop and the rest of the voltage is consumed in V4 which is giving us the total voltage supply.
V1 + V2 = V3 and V3 + V4 = SV

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